The information given about number of project handle by two companies (A and B) in three different years (2015, 2016 and 2017). Read the information carefully and answer the questions given below. In 2015, Total projects handle by A are 1.5 times of B. In 2016, Total project handle by B is 9 more than that of in 2015 and A handle 20 projects. In 2017, total project handle by A is 25% more than that of by B in 2015 and B handle 30 projects. Total projects handle by A in all three years is 42. What is the percentage difference between the number of projects handled by company A in 2016 and the number of projects handled by company B in 2015? Is it more or less, and by how much?

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**Solution:**

1. Let the number of projects handled by company B in 2015 be *x*.

2. According to the problem, company A handled 1.5 times the projects of B in 2015:
   $$A_{2015} = 1.5x$$

3. Company B handled 9 more projects in 2016 than in 2015:
   $$B_{2016} = x + 9$$

4. Company A handled 20 projects in 2016:
   $$A_{2016} = 20$$

5. In 2017, company A handled 25% more projects than company B did in 2015:
   $$A_{2017} = 1.25x$$

6. Company B handled 30 projects in 2017:
   $$B_{2017} = 30$$

7. Total projects handled by company A over the three years is 42:
   $$A_{2015} + A_{2016} + A_{2017} = 42$$
   Substitute the values:
   $$1.5x + 20 + 1.25x = 42$$

8. Combine like terms:
   $$2.75x + 20 = 42$$

9. Solve for *x*:
   $$2.75x = 42 - 20 = 22$$
   $$x = \frac{22}{2.75} = 8$$

10. Number of projects handled by company B in 2015 is 8.

11. Number of projects handled by company A in 2016 is 20.

12. Calculate the percentage by which A's 2016 projects exceed B's 2015 projects:
    $$	ext{Percentage increase} = \frac{20 - 8}{8} 	imes 100 = \frac{12}{8} 	imes 100 = 150\%$$

**Answer:** 150\%

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