Six persons are arranged in descending order according to their weight from left to right. Only T is lighter than Q whose weight is 17 kg. S is twice as heavy as Q and 14 kg lighter than N. There are two persons between M and S. R is not the second heaviest among all.
What may be the possible weight of R?

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**Solution:**

1. Given that Q weighs 17 kg and only T is lighter than Q, so T < Q = 17 kg.

2. S is twice as heavy as Q, so:
   $$ S = 2 	imes 17 = 34 	ext{ kg} $$

3. S is 14 kg lighter than N, so:
   $$ N = S + 14 = 34 + 14 = 48 	ext{ kg} $$

4. The order is descending from left to right, so the heaviest is on the left.

5. There are two persons between M and S. Since S is 34 kg and N is 48 kg, and M is heavier than N, M must be heavier than 48 kg.

6. R is not the second heaviest, so R cannot be just after M.

7. The possible order with weights is:
   $$ M > N (48 	ext{ kg}) > R > S (34 	ext{ kg}) > Q (17 	ext{ kg}) > T $$

8. Since R is between N and S, R's weight must be between 48 kg and 34 kg.

9. Among the options, only 39 kg fits this condition.

**Answer:** 39 kg

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