The average present age of A, B, and C is $29$ years. If A's age is $2$ years less than B's age, and B's age is $8$ years less than C's age, what is the present age of A?

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**Solution:**

1. Let the ages of A, B, and C be $a$, $b$, and $c$ respectively.

2. Given the average age of A, B, and C is $29$ years, so:
   $$\frac{a + b + c}{3} = 29 \implies a + b + c = 87$$

3. Given that A's age is $2$ years less than B's age:
   $$a = b - 2$$

4. Also, B's age is $8$ years less than C's age:
   $$b = c - 8$$

5. Substitute $a$ and $b$ in terms of $c$ into the sum equation:
   $$a + b + c = (b - 2) + b + c = 87$$

Replace $b$ with $c - 8$:
   $$ (c - 8 - 2) + (c - 8) + c = 87$$

6. Simplify:
   $$ (c - 10) + (c - 8) + c = 87$$
   $$ 3c - 18 = 87$$

7. Solve for $c$:
   $$ 3c = 87 + 18 = 105$$
   $$ c = \frac{105}{3} = 35$$

8. Find $b$:
   $$ b = c - 8 = 35 - 8 = 27$$

9. Find $a$:
   $$ a = b - 2 = 27 - 2 = 25$$

**Answer:** $25 	ext{ years}$

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