Two pipes A and B can fill a tank in 40 minutes and 60 minutes respectively. Pipe C is an emptying pipe whose efficiency is 25\% more than that of pipe B. Find the time taken by pipes A, B, and C together to fill the tank.

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**Solution:**

1. Calculate the filling rates of pipes A and B:
   - Pipe A fills the tank in 40 minutes, so its rate is $\frac{1}{40}$ tank per minute.
   - Pipe B fills the tank in 60 minutes, so its rate is $\frac{1}{60}$ tank per minute.

2. Determine the emptying rate of pipe C:
   - Pipe C's efficiency is 25\% more than pipe B's filling rate.
   - So, pipe C empties at a rate of $1.25 	imes \frac{1}{60} = \frac{1.25}{60} = \frac{5}{240} = \frac{1}{48}$ tank per minute.

3. Calculate the net rate when all three pipes are working together:
   - Net rate = Rate of A + Rate of B - Rate of C
   - Net rate = $\frac{1}{40} + \frac{1}{60} - \frac{1}{48}$

4. Find the common denominator for 40, 60, and 48:
   - LCM of 40, 60, and 48 is 240.

5. Convert rates to have denominator 240:
   - $\frac{1}{40} = \frac{6}{240}$
   - $\frac{1}{60} = \frac{4}{240}$
   - $\frac{1}{48} = \frac{5}{240}$

6. Calculate net rate:
   - Net rate = $\frac{6}{240} + \frac{4}{240} - \frac{5}{240} = \frac{5}{240}$ tank per minute.

7. Calculate the total time taken to fill the tank:
   - Time = $\frac{1}{	ext{Net rate}} = \frac{1}{\frac{5}{240}} = \frac{240}{5} = 48$ minutes.

**Answer:** 48 minutes

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