Find the average of five consecutive natural numbers if the largest number is 40\% more than the smallest number.

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**Solution:**

1. Let the smallest number be *x*. Since the numbers are consecutive, the five numbers are:
   $$x, (x+1), (x+2), (x+3), (x+4)$$

2. The largest number is given as 40\% more than the smallest number:
   $$x + 4 = x + 0.4x = 1.4x$$

3. Simplify the equation:
   $$x + 4 = 1.4x$$
   $$4 = 1.4x - x = 0.4x$$
   $$x = \frac{4}{0.4} = 10$$

4. The five numbers are:
   $$10, 11, 12, 13, 14$$

5. Calculate the average:
   $$	ext{Average} = \frac{10 + 11 + 12 + 13 + 14}{5} = \frac{60}{5} = 12$$

**Answer:** 12

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