Pipe A can fill $ $\frac{3}{5}$ $ of a tank in 9 minutes. Pipe B is 50\% more efficient than pipe A, and pipe C is 50\% less efficient than pipe B. How long will it take for all three pipes working together to fill the entire tank?

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**Solution:**

- Pipe A fills tank in 15 min
- Pipe B is twice as efficient as A (efficiency ratio 2:1)
- Pipe C is half as efficient as B (efficiency ratio 1:2)

Times:
- A = 15 min
- B = 7.5 min
- C = 15 min

Combined rate:

$$\frac{1}{15} + \frac{1}{7.5} + \frac{1}{15} = \frac{1}{15} + \frac{2}{15} + \frac{1}{15} = \frac{4}{15}$$

Time taken together:

$$\frac{1}{\frac{4}{15}} = \frac{15}{4} = 3.75 	ext{ minutes}$$

**Answer:** 3.75 minutes

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