What is the approximate value of the expression:

$$\sqrt[3]{729.14} + 11.01^3 + 60.24\% ext{ of } 449.86 = ?$$

(You are not expected to calculate the exact value, just the approximate one.)

Question

What is the approximate value of the expression:

$$\sqrt[3]{729.14} + 11.01^3 + 60.24\% 	ext{ of } 449.86 = ?$$

(You are not expected to calculate the exact value, just the approximate one.)

Accepted Answer

**Solution:**

1. Approximate the cube root:
   - $\sqrt[3]{729.14} \approx \sqrt[3]{729} = 9$

2. Approximate the cube of $11.01$:
   - $11.01^3 \approx 11^3 = 1331$

3. Calculate $60.24\%$ of $449.86$:
   - $60\%$ of $450$ is $270$, so $60.24\%$ of $449.86 \approx 0.6024 	imes 450 = 271$

4. Add all approximations:
   - $9 + 1331 + 271 = 1611$

Since the question asks for an approximate value, the closest option is $1610$.

**Answer:** $1610$

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