Veer and Anurag invested Rs. $x$ and Rs. $x + 300$ respectively for 2 years. Veer invested his amount at simple interest at the rate of 10\% per annum, while Anurag invested his amount at compound interest at 12.5\% per annum, compounded annually. If Anurag received Rs. 480 more as interest than Veer, find the amount invested by Anurag.

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**Solution:**

1. Let Veer's investment be Rs. $x$. Then Anurag's investment is Rs. $x + 300$.

2. Calculate Veer's simple interest (SI) for 2 years at 10\% per annum:
   $$	ext{SI} = \frac{P 	imes R 	imes T}{100} = \frac{x 	imes 10 	imes 2}{100} = \frac{20x}{100} = 0.2x$$

3. Calculate Anurag's compound interest (CI) for 2 years at 12.5\% per annum:
   - Rate $R = 12.5\% = \frac{25}{2}\% = 0.125$ (in decimal)
   - Amount after 2 years:
     $$A = P 	imes (1 + R)^2 = (x + 300) 	imes (1 + 0.125)^2 = (x + 300) 	imes (1.125)^2 = (x + 300) 	imes 1.265625$$
   - Compound interest:
     $$	ext{CI} = A - P = (x + 300) 	imes 1.265625 - (x + 300) = (x + 300)(1.265625 - 1) = (x + 300) 	imes 0.265625$$

4. According to the problem, Anurag's interest exceeds Veer's by Rs. 480:
   $$	ext{CI} - 	ext{SI} = 480$$
   Substitute the values:
   $$0.265625(x + 300) - 0.2x = 480$$

5. Expand and simplify:
   $$0.265625x + 79.6875 - 0.2x = 480$$
   $$0.065625x + 79.6875 = 480$$
   $$0.065625x = 480 - 79.6875 = 400.3125$$

6. Solve for $x$:
   $$x = \frac{400.3125}{0.065625} = 6100$$

7. Amount invested by Anurag:
   $$x + 300 = 6100 + 300 = 6400$$

**Answer:** Rs. 6400

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