A man bought two different articles A and B for the same cost price. He sold article A at a profit of 20% and article B at a loss of 10%. If his overall profit from both articles is Rs. 40, what is the cost price of each article?

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**Solution:**

1. Let the cost price of each article be *x*.

2. Selling price of article A = Cost price + 20% profit = $x + 0.20x = 1.20x$

3. Selling price of article B = Cost price - 10% loss = $x - 0.10x = 0.90x$

4. Total cost price for both articles = $x + x = 2x$

5. Total selling price for both articles = $1.20x + 0.90x = 2.10x$

6. Overall profit = Total selling price - Total cost price = $2.10x - 2x = 0.10x$

7. Given overall profit is Rs. 40, so:
   $$0.10x = 40$$
   $$x = \frac{40}{0.10} = 400$$

**Answer:** Rs. 400

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