If 1 is subtracted from every odd digit of the number $735383629$, and then all the resulting digits are arranged in ascending order from left to right, what is the sum of the 2nd, 4th, 6th, and 7th digits (from the left) of the new number formed?

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**Solution:**

1. Identify the digits of the number: $7, 3, 5, 3, 8, 3, 6, 2, 9$.

2. Subtract 1 from each odd digit:
   - Odd digits are $7, 3, 5, 3, 3, 9$.
   - After subtracting 1: $7 	o 6$, $3 	o 2$, $5 	o 4$, $3 	o 2$, $3 	o 2$, $9 	o 8$.

3. Even digits remain unchanged: $8, 6, 2$.

4. Replace the original digits with the new digits:
   - Original digits: $7, 3, 5, 3, 8, 3, 6, 2, 9$
   - New digits: $6, 2, 4, 2, 8, 2, 6, 2, 8$

5. Arrange all these digits in ascending order:
   - Digits: $2, 2, 2, 2, 4, 6, 6, 8, 8$

6. Identify the 2nd, 4th, 6th, and 7th digits:
   - 2nd digit: $2$
   - 4th digit: $2$
   - 6th digit: $6$
   - 7th digit: $6$

7. Calculate their sum:
   $$2 + 2 + 6 + 6 = 16$$

**Answer:** $16$

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