The average age of a group of 20 students is calculated as 18 years. However, during the calculation, the ages of two students, 16 years and 15 years, were mistakenly taken as 18 years and 20 years respectively. What is the correct average age of the group?

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**Solution:**

1. Calculate the total age based on the incorrect average:
   - Total age = Average × Number of students = $18 	imes 20 = 360$

2. Calculate the sum of the ages that were wrongly taken:
   - Incorrect sum = $18 + 20 = 38$

3. Calculate the actual sum of the ages of those two students:
   - Actual sum = $16 + 15 = 31$

4. Adjust the total age by subtracting the incorrect sum and adding the correct sum:
   - Correct total age = $360 - 38 + 31 = 353$

5. Find the correct average age:
   $$	ext{Correct average} = \frac{353}{20} = 17.65$$

**Answer:** $17.65$

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