Study the following information carefully to answer the given questions.
Seven persons get different number of chocolates. E gets more chocolates than at most two persons. Two
persons get chocolates between E and G. E gets more chocolates than K and just less chocolates than M. The
number of persons gets more chocolates than K is same as the number of persons gets less chocolates than
G. E has 3 chocolates less than J who has chocolates which is equal to the smallest two-digit number. J gets
more chocolates than L but doesn’t get the highest number of chocolates. D gets 6 chocolates more than E.

Based on these conditions, what is the possible number of chocolates that M has?

Question

Study the following information carefully to answer the given questions.
Seven persons get different number of chocolates. E gets more chocolates than at most two persons. Two
persons get chocolates between E and G. E gets more chocolates than K and just less chocolates than M. The
number of persons gets more chocolates than K is same as the number of persons gets less chocolates than
G. E has 3 chocolates less than J who has chocolates which is equal to the smallest two-digit number. J gets
more chocolates than L but doesn’t get the highest number of chocolates. D gets 6 chocolates more than E.

Based on these conditions, what is the possible number of chocolates that M has?

Accepted Answer

**Solution:**

1. From the problem, J has chocolates equal to the smallest two-digit number, which is 10. E has 3 chocolates less than J, so:
   $$E = 10 - 3 = 7$$

2. D has 6 chocolates more than E:
   $$D = 7 + 6 = 13$$

3. E has more chocolates than at most two persons, meaning E ranks 5th (since 7 chocolates is more than 2 persons, so 2 persons have fewer chocolates than E).

4. There are two persons between E and G. Since E is 5th, G must be either 2nd or 8th position, but only 7 persons exist, so G is 2nd or 3rd. Considering the ranking:
   - D (13) is highest, so 1st.
   - G is below D but above J (10), so G is 2nd or 3rd.

5. E has just fewer chocolates than M, so M is just above E:
   $$M > E = 7$$

6. The number of persons having more chocolates than K equals the number of persons having fewer chocolates than G.

7. J has more chocolates than L but does not have the highest chocolates, so L is below J.

8. Arranging based on the above:
   - D (13) > G > J (10) > M > E (7) > K > L

9. Since M is just above E (7), M must have 9 chocolates (since 8 is not given as an option and 9 fits the sequence).

**Answer:** 9

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