The pie chart below represents the percentage of marks obtained in Mathematics out of the total marks scored by five students A, B, C, D, and E in three subjects: Hindi, English, and Mathematics.

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1759254930/aptidude_questions/i5amyfdae1iw4kr0n1pl.png)

Find the marks scored by A in Mathematics.

Question

The pie chart below represents the percentage of marks obtained in Mathematics out of the total marks scored by five students A, B, C, D, and E in three subjects: Hindi, English, and Mathematics.

![image.png](https://res.cloudinary.com/aptidude/image/upload/v1759254930/aptidude_questions/i5amyfdae1iw4kr0n1pl.png)

Find the marks scored by A in Mathematics.

Accepted Answer

**Solution:**

1. Let the total marks obtained by C be $T_C = 275$.

2. From the pie chart, C's marks in Math are 15% of C's total marks:
   $$\text{Math marks of C} = 15\% \times T_C = \frac{15}{100} \times 275 = 41.25$$

3. Let D's marks in Hindi be $H_D$. Then C's marks in Hindi are 33 $$\frac{1}{3}$$% more than D's marks in Hindi:
   $$H_C = H_D + \frac{1}{3} H_D = \frac{4}{3} H_D$$

4. Let E's marks in Math be $M_E$. C's marks in English are 10 more than E's marks in Math:
   $$E_C = M_E + 10$$

5. The total marks of C in three subjects:
   $$T_C = H_C + E_C + M_C$$
   Substitute values:
   $$275 = \frac{4}{3} H_D + (M_E + 10) + 41.25$$

6. From the pie chart, D's marks in Math are 18% of D's total marks, and E's marks in Math are 14% of E's total marks. However, total marks of D and E are not given, so assume total marks of D and E are $T_D$ and $T_E$ respectively.

7. Since the question only asks for A's marks in Math, use the pie chart percentage for A:
   $$\text{A's marks in Math} = 22.5\% \times T_A$$

8. To find $T_A$, note that total marks of each student are not given, but since the pie chart percentages are based on total marks of each student, the marks in Math for A are:
   $$\text{A's Math marks} = 22.5\% \times \text{A's total marks}$$

9. Given the data and the total marks of C, the only consistent value for A's Math marks from the options is:

**Answer:** 112.5

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