If 1 is added to each even digit and 2 is subtracted from each odd digit in the number $39225685459$, then how many digits will appear more than twice in the new number thus formed?

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**Solution:**

1. Write down the original number: $39225685459$

2. Apply the given transformation rules to each digit:
   - For even digits, add 1
   - For odd digits, subtract 2

3. Identify each digit and transform:
   - 3 (odd): $3 - 2 = 1$
   - 9 (odd): $9 - 2 = 7$
   - 2 (even): $2 + 1 = 3$
   - 2 (even): $2 + 1 = 3$
   - 5 (odd): $5 - 2 = 3$
   - 6 (even): $6 + 1 = 7$
   - 8 (even): $8 + 1 = 9$
   - 5 (odd): $5 - 2 = 3$
   - 4 (even): $4 + 1 = 5$
   - 5 (odd): $5 - 2 = 3$
   - 9 (odd): $9 - 2 = 7$

4. The new number formed is: $1 7 3 3 3 7 9 3 5 3 7$

5. Count the frequency of each digit:
   - 1 appears 1 time
   - 3 appears 5 times
   - 5 appears 1 time
   - 7 appears 3 times
   - 9 appears 1 time

6. Digits appearing more than twice are 3 and 7 (two digits).

**Answer:** Two

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