The present age of Harish is 8 times the sum of the ages of his two sons. After 8 years, his age will be twice the sum of the ages of his sons. What is Harish’s present age?

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### Solution:  
1. **Define variables:**  
   - Let the sum of the ages of Harish’s sons be $$ x $$.  
   - Harish’s present age = $$ 8x $$.

2. **Equation after 8 years:**  
   - Harish’s age after 8 years = $$ 8x + 8 $$.  
   - Sum of sons’ ages after 8 years = $$ x + 16 $$ (since each son ages 8 years).  
   - According to the problem:  
     $$
     8x + 8 = 2(x + 16)
     $$

3. **Solve for $$ x $$:**  
   $$
   8x + 8 = 2x + 32 \quad \Rightarrow \quad 6x = 24 \quad \Rightarrow \quad x = 4
   $$

4. **Harish’s present age:**  
   $$
   8x = 8 	imes 4 = 32
   $$

**Verification:**  
- After 8 years, Harish’s age = $$ 32 + 8 = 40 $$.  
- Sons’ total age after 8 years = $$ 4 + 16 = 20 $$.  
- $$ 40 = 2 	imes 20 $$, which satisfies the condition.

Thus, the correct answer is **32**.

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