In a triangle PQR, if $$ \angle P + \angle R = 130^\circ $$ and $$ \angle P + 3\angle Q = 170^\circ $$, then $$ \angle P $$ is:

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#### Step 1: Use the Angle Sum Property of a Triangle
In any triangle, the sum of the angles is:  
$$
\angle P + \angle Q + \angle R = 180^\circ.
$$

#### Step 2: Substitute Given Conditions
It is given that:  
1. $$ \angle P + \angle R = 130^\circ $$.  
2. $$ \angle P + 3\angle Q = 170^\circ $$.

From the first equation:  
$$
\angle Q = 180^\circ - (\angle P + \angle R) = 180^\circ - 130^\circ = 50^\circ.
$$

#### Step 3: Solve for $$ \angle P $$
Substitute $$ \angle Q = 50^\circ $$ into the second equation:  
$$
\angle P + 3(50^\circ) = 170^\circ.
$$  
Simplify:  
$$
\angle P + 150^\circ = 170^\circ.
$$  
$$
\angle P = 170^\circ - 150^\circ = 20^\circ.
$$

Thus, the value of $$ \angle P $$ is **20°**, making Option **2** correct.

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