Given two series:

**Series I:** 60, 120, 24, 48, 9.6, 19.2

**Series II:** 100, W, X, Y, Z, 32

Both series follow the same pattern. Find the difference between $(Y + X)$ and $(Y + Z)$.

Question

Given two series:

**Series I:** 60, 120, 24, 48, 9.6, 19.2

**Series II:** 100, W, X, Y, Z, 32

Both series follow the same pattern. Find the difference between $(Y + X)$ and $(Y + Z)$.

Accepted Answer

**Solution:**

1. Analyze **Series I:** 60, 120, 24, 48, 9.6, 19.2
   - The pattern alternates between multiplying by 2 and dividing by 5:
     - $60 	imes 2 = 120$
     - $120 \div 5 = 24$
     - $24 	imes 2 = 48$
     - $48 \div 5 = 9.6$
     - $9.6 	imes 2 = 19.2$

2. Apply the same pattern to **Series II:** 100, W, X, Y, Z, 32
   - Starting with 100:
     - $W = 100 	imes 2 = 200$
     - $X = 200 \div 5 = 40$
     - $Y = 40 	imes 2 = 80$
     - $Z = 80 \div 5 = 16$
     - Check last term: $16 	imes 2 = 32$ (matches given)

3. Calculate the required difference:
   - $(Y + X) - (Y + Z) = (80 + 40) - (80 + 16) = 120 - 96 = 24$

**Answer:** 24

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