Find the a$45\degree$ngle of elevation of the Sun when the length of the shadow of a tree is $$ \frac{1}{\sqrt{3}} $$ times the height of the tree.

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$30\degree$
Let the height of the tree be $$ h $$, and the length of its shadow be $$ \frac{h}{\sqrt{3}} $$. The angle of elevation is denoted by $$ 	heta $$.

1. **Use the tangent formula for angle of elevation:**  
   $$ 
   	an 	heta = \frac{	ext{Height of Tree}}{	ext{Length of Shadow}} 
   $$  
   Substituting the values:  
   $$ 
   	an 	heta = \frac{h}{\frac{h}{\sqrt{3}}} 
   $$

2. **Simplify the equation:**  
   $$ 
   	an 	heta = \sqrt{3} 
   $$

3. **Find $$ 	heta $$:**  
   From trigonometric tables, $$ 	an 60^\circ = \sqrt{3} $$. Therefore,  
   $$ 
   	heta = 60^\circ. 
   $$

Thus, the angle of elevation is **$$ 60^\circ $$**.

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