What is the probability that any non-leap year will have 53 Sundays?

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A non-leap year has **365 days**, which equals **52 full weeks and 1 extra day**.

1. **Number of Sundays in 52 weeks:**  
   Each week has one Sunday, so there are **52 Sundays** in 52 weeks.

2. **Extra day in a non-leap year:**  
   The extra day can be any of the 7 days of the week: Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, or Saturday.

3. **Condition for 53 Sundays:**  
   For a non-leap year to have 53 Sundays, the extra day must be a Sunday. There is only **1 favorable outcome (Sunday)** out of the **7 possible outcomes (days of the week)**.

4. **Probability formula:**  
   Probability = $$ \frac{	ext{Favorable outcomes}}{	ext{Total outcomes}} $$  
   Substituting values:  
   $$ P(	ext{53 Sundays}) = \frac{1}{7}. $$

Thus, the probability that a non-leap year has 53 Sundays is **$$ \frac{1}{7} $$**, which corresponds to option **(c)**.

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