Car ‘X’ travels for 4 hours to reach from point A to B. Car ‘Y’ travels at the speed of 70 kmph to reach from point B to C in 3 hours. Distance travelled by car ‘X’ to cover point A to B is $ \frac{1}{7} $ more than distance travelled by car ‘Y’. How much time will car ‘X’ take to reach from point A to C?

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**Solution:**

1. Calculate distance travelled by car Y from B to C:
   - Speed of car Y = 70 kmph
   - Time = 3 hours
   - Distance = Speed × Time = 70 × 3 = 210 km

2. Distance travelled by car X from A to B is $ \frac{1}{7} $ more than distance travelled by car Y:
   - Distance by car X = Distance by car Y × $ 1 + \frac{1}{7} $ = 210 × $ \frac{8}{7} $ = 240 km

3. Speed of car X:
   - Time taken = 4 hours
   - Speed = Distance / Time = 240 / 4 = 60 kmph

4. Total distance from A to C = Distance A to B + Distance B to C = 240 + 210 = 450 km

5. Time taken by car X to travel from A to C:
   - Time = Total distance / Speed = 450 / 60 = 7.5 hours

**Answer:** 7.5 hours

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