In order to gain 10 more points than car S, how many total drifts should car P have made, if car P's time and number of crashes remain the same?

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**Solution:**

1. Calculate points earned by car S:
   - Points = (Points per drift × Number of drifts) − (Points lost per crash × Number of crashes)
   - Given: 50 points per drift, 20 points lost per crash
   - Car S: 50 × 8 − 20 × 6 = 400 − 120 = 280 points

2. Let the number of drifts made by car P be *N*.
   - Car P's crashes and time remain the same, so crashes = 3
   - Points for car P = 50 × N − 20 × 3

3. Car P needs to gain 10 more points than car S:
   $$50N - 20 	imes 3 = 280 + 10$$
   $$50N - 60 = 290$$
   $$50N = 350$$
   $$N = \frac{350}{50} = 7$$

**Answer:** 7

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