Another car named T makes the total number of drifts same as that of car R and it still receives 0 points at the end. If each drift gives 50 points and each crash deducts 20 points, how many crashes must car T have suffered?

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**Solution:**

1. Let the number of crashes suffered by car T be *N*.

2. Each drift gives 50 points and each crash deducts 20 points.

3. Given that car T makes the total number of drifts same as car R, which is 6 drifts.

4. The total points for car T is zero:
   
   $$50 	imes 6 - 20 	imes N = 0$$

5. Simplify the equation:
   
   $$300 - 20N = 0$$

6. Rearranging:
   
   $$20N = 300$$

7. Divide both sides by 20:
   
   $$N = \frac{300}{20} = 15$$

**Answer:** 15

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