Speed of car S is what percentage more than that of car Q?

Given:
- Distance covered by both cars = 3000 m
- Time taken by car S = 100 s
- Time taken by car Q = 120 s

Calculate the percentage increase in speed of car S compared to car Q.

Question

Speed of car S is what percentage more than that of car Q?

Given:
- Distance covered by both cars = 3000 m
- Time taken by car S = 100 s
- Time taken by car Q = 120 s

Calculate the percentage increase in speed of car S compared to car Q.

Accepted Answer

**Solution:**

1. Calculate speed of car S:
   $$	ext{Speed}_S = \frac{	ext{Distance}}{	ext{Time}} = \frac{3000}{100} = 30 	ext{ m/s}$$

2. Calculate speed of car Q:
   $$	ext{Speed}_Q = \frac{3000}{120} = 25 	ext{ m/s}$$

3. Calculate percentage increase in speed of car S over car Q:
   $$	ext{Percentage Increase} = \frac{	ext{Speed}_S - 	ext{Speed}_Q}{	ext{Speed}_Q} 	imes 100 = \frac{30 - 25}{25} 	imes 100 = 20\%$$

**Answer:** 20\%

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