Find the respective ratio of the curved surface area of tank P to the total surface area of tank R.

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**Solution:**

1. Given data involves two tanks P and R, presumably cylindrical.

2. For tank P:
   - Radius $r_P = 21 \text{ m}$ (calculated from given data)
   - Height $h_P = 28 \text{ m}$

3. For tank R:
   - Radius $r_R = 7 \text{ m}$
   - Height $h_R = 35 \text{ m}$

4. Calculate curved surface area (CSA) of tank P:
   $$\text{CSA}_P = 2 \pi r_P h_P = 2 \times \frac{22}{7} \times 21 \times 28$$

5. Calculate total surface area (TSA) of tank R:
   $$\text{TSA}_R = 2 \pi r_R (r_R + h_R) = 2 \times \frac{22}{7} \times 7 \times (7 + 35)$$

6. Compute the ratio:
   $$
   \frac{\text{CSA}_P}{\text{TSA}_R} = \frac{2 \times \frac{22}{7} \times 21 \times 28}{2 \times \frac{22}{7} \times 7 \times 42} = \frac{21 \times 28}{7 \times 42} = \frac{21}{7} \times \frac{28}{42} = 3 \times \frac{2}{3} = 2
   $$

7. Therefore, the ratio is $2:1$.

**Answer:** 2:1

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