Another tank Z has its height as 20\% more than that of tank R and radius as 20\% more than that of tank P. What is the sum of curved surface area of tank P and Z together (approximately)?

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**Solution:**

1. Given:
   - Height of tank Z is 20\% more than height of tank R.
   - Radius of tank Z is 20\% more than radius of tank P.

2. From the solution provided:
   - Height of tank Z = $35 	imes \frac{120}{100} = 42 	ext{ m}$
   - Radius of tank P = $\sqrt{38808 	imes \frac{7}{22} 	imes \frac{1}{28}} = 21 	ext{ m}$
   - Radius of tank Z = $21 	imes \frac{6}{5} = 25.2 \approx 25 	ext{ m}$

3. Curved Surface Area (CSA) of a cylinder = $2 \pi r h$

4. Calculate CSA of tank P:
   $$	ext{CSA}_P = 2 	imes \frac{22}{7} 	imes 21 	imes 28 = 2 	imes \frac{22}{7} 	imes 588 = 2 	imes 1848 = 3696 	ext{ m}^2$$

5. Calculate CSA of tank Z:
   $$	ext{CSA}_Z = 2 	imes \frac{22}{7} 	imes 25 	imes 42 = 2 	imes \frac{22}{7} 	imes 1050 = 2 	imes 3300 = 6600 	ext{ m}^2$$

6. Sum of curved surface areas:
   $$3696 + 6600 = 10296 	ext{ m}^2$$

**Answer:** 10296 m²

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