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Question

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Accepted Answer

**Solution:**

1. Let the total number of employees in company B be $100x$.

2. Total female employees = 40\% of $100x$ = $40x$.

3. Percentage of managers in company B is given as 25\%, so total managers = 25\% of $100x$ = $25x$.

4. Therefore, total non-manager employees = $100x - 25x = 75x$.

5. Among non-managers, 40\% are female, so female non-managers = 40\% of $75x = 30x$.

6. Female managers = total female employees - female non-managers = $40x - 30x = 10x$.

7. Given female managers = 56, so:
   $$10x = 56 \implies x = \frac{56}{10} = 5.6$$

8. Total non-manager employees = $75x = 75 	imes 5.6 = 420$.

**Answer:** 420

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