In company C, the total number of male managers is 100 and the total number of female employees is 260. If the total number of employees in company C is such that managers constitute 30% of the total employees, find by what percentage the total number of male employees (including both managers and non-managers) exceeds the number of male managers in company C.

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**Solution:**

1. Let the total number of employees in company C be $100x$.

2. Given that managers form 30\% of total employees, so total managers = $30\%$ of $100x = 30x$.

3. The total number of male managers is given as 100, and the total number of female managers is 80 (from the table data). Therefore,
   $$30x = 100 + 80 = 180 \implies x = \frac{180}{30} = 6$$

4. Hence, total employees = $100x = 100 \times 6 = 600$.

5. Total female employees are given as 260.

6. Therefore, total male employees (including managers and non-managers) = Total employees - Total female employees = $600 - 260 = 340$.

7. We need to find by what percentage the total male employees exceed the number of male managers:
   $$
   \text{Required percentage} = \frac{340 - 100}{100} \times 100 = \frac{240}{100} \times 100 = 240\% 
   $$

**Answer:** $240\%$

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