In company A, the difference between the total number of managers and the total number of non-manager employees is 288. Given that 20% of the total employees are managers and there are 32 female managers, what is the total number of male managers in company A?

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**Solution:**

1. Let the total number of employees in company A be $100x$.

2. Since 20% of employees are managers, total managers = $20\%$ of $100x = 20x$.

3. Number of female managers is given as 32, so male managers = $20x - 32$.

4. Number of non-manager employees = total employees - managers = $100x - 20x = 80x$.

5. According to the problem, the difference between non-managers and managers is 288:
   $$80x - 20x = 288$$
   $$60x = 288$$
   $$x = \frac{288}{60} = 4.8$$

6. Total male managers = $20x - 32 = 20 	imes 4.8 - 32 = 96 - 32 = 64$.

**Answer:** 64

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