In company D, the total number of non-manager employees is 612. Given that managers constitute 15\% of the total employees in company D, and the number of female managers is 50, what is the total number of male managers in company D?

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**Solution:**

1. Let the total number of employees in company D be $100x$.

2. Since managers are 15\% of total employees, non-managers are 85\% of total employees.

3. Given, number of non-manager employees = 612, so:
   
   $$85x = 612$$

4. Solving for $x$:
   
   $$x = \frac{612}{85} = 7.2$$

5. Total number of managers in company D:
   
   $$15\% 	ext{ of } 100x = 15x = 15 	imes 7.2 = 108$$

6. Number of female managers is given as 50.

7. Therefore, number of male managers:
   
   $$108 - 50 = 58$$

**Answer:** $58$

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