Given the number of male and female students in classes A and B as follows:

| Class | Boys | Girls |
|-------|-------|-------|
| A | 50 | 70 |
| B | ? | 80 |

If the number of boys in class B is equal to the number of girls in class B, by what percentage are the total students in class B more than those in class A?

Question

Given the number of male and female students in classes A and B as follows:

| Class | Boys | Girls |
|-------|-------|-------|
| A     | 50    | 70    |
| B     | ?     | 80    |

If the number of boys in class B is equal to the number of girls in class B, by what percentage are the total students in class B more than those in class A?

Accepted Answer

**Solution:**

1. According to the problem, the number of boys in class B equals the number of girls in class B, which is 80. Therefore, boys in class B = 80.

2. Total students in class B = boys + girls = 80 + 80 = 160.

3. For class A, boys are given as 50. Using the probability information (not shown here but given in the original data), girls in class A are 70.

4. Total students in class A = 50 + 70 = 120.

5. To find the percentage by which class B students are more than class A students:

$$	ext{Percentage increase} = \frac{160 - 120}{120} 	imes 100 = \frac{40}{120} 	imes 100 = 33 \frac{1}{3} \%$$

**Answer:** 33 \frac{1}{3} \%

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