Two dice are thrown simultaneously. What is the probability that the sum of the two numbers is 4?

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Accepted Answer

When two dice are rolled, each die has 6 possible outcomes, resulting in a total of $$ 6 	imes 6 = 36 $$ outcomes.

To achieve a sum of 4, the possible pairs are:  
- $$ (1, 3) $$: First die shows 1 and second die shows 3.  
- $$ (2, 2) $$: Both dice show 2.  
- $$ (3, 1) $$: First die shows 3 and second die shows 1.

Thus, there are 3 favorable outcomes.

The probability is calculated as:  
$$
	ext{Probability} = \frac{	ext{Number of favorable outcomes}}{	ext{Total number of outcomes}} = \frac{3}{36} = \frac{1}{12}
$$

Therefore, the correct answer is **(b) $$ \frac{1}{12} $$**.

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