A water tank with a capacity of 600,000 L supplies water continuously to a building with 40 flats. Each flat has a tap with a flow rate of 250 L/h in November, when 50% of the flats are occupied. In December, 30 flats are occupied, and the tank empties after $4 \frac{1}{6}$ days. The flow rate from each tap in December is $A\%$ more or less than that in November. Calculate the value of $A\%$.

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**Solution:**

1. Convert the time for which the tank empties in December into hours:
   - Given $4 \frac{1}{6}$ days = $\frac{25}{6}$ days
   - Hours = $\frac{25}{6} \times 24 = 100$ hours

2. Calculate the flow rate per tap in December:
   - Total water = 600,000 L
   - Number of flats occupied in December = 30
   - Total time = 100 hours
   - Flow rate per tap = $\frac{600000}{30 \times 100} = 200$ L/h

3. Calculate the percentage change $A\%$ in flow rate from November to December:
   - November flow rate = 250 L/h
   - December flow rate = 200 L/h
   - Percentage decrease:
     $$A\% = \frac{250 - 200}{250} \times 100 = 20\%$$

**Answer:** 20\%

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