In October, the efficiency of each tap decreases by 20% compared to the efficiency in November due to leakage, and the capacity of the water tank is reduced to 80% of its original capacity of 600,000 liters. If the number of occupied flats in October is the same as the number of occupied flats in December (which is 30), how many hours will it take for the tank to be emptied in October?

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**Solution:**

1. The original efficiency of each tap in November is given as 250 L/hour.

2. In October, efficiency decreases by 20%, so the new efficiency per tap is:
   $$250 - 20\% 	imes 250 = 250 	imes \frac{4}{5} = 200 	ext{ L/hour}$$

3. The tank capacity is reduced to 80% of 600,000 L:
   $$600000 	imes \frac{4}{5} = 480000 	ext{ L}$$

4. Number of occupied flats in October is equal to December, which is 30.

5. Total water flow per hour from all taps:
   $$200 	imes 30 = 6000 	ext{ L/hour}$$

6. Time taken to empty the tank:
   $$\frac{480000}{6000} = 80 	ext{ hours}$$

**Answer:** 80 hours

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