Calculate the value of '?' in the equation:

$$39.95\% ext{ of } 265 + 35.2\% ext{ of } 178 = 50\% ext{ of } ? + ?\% ext{ of } 80$$

Question

Calculate the value of '?' in the equation:

$$39.95\% 	ext{ of } 265 + 35.2\% 	ext{ of } 178 = 50\% 	ext{ of } ? + ?\% 	ext{ of } 80$$

Accepted Answer

**Solution:**

1. Calculate each percentage term on the left side:
   - $39.95\%$ of $265 = \frac{39.95}{100} 	imes 265 = 0.3995 	imes 265 = 105.8675$
   - $35.2\%$ of $178 = \frac{35.2}{100} 	imes 178 = 0.352 	imes 178 = 62.656$

2. Sum these two values:
   $$105.8675 + 62.656 = 168.5235$$

3. Let the unknown value be $x$ and the unknown percentage be $p\%$.

The right side is:
   $$50\% 	ext{ of } x + p\% 	ext{ of } 80 = 0.5x + \frac{p}{100} 	imes 80 = 0.5x + 0.8p$$

4. Since the equation is:
   $$168.5235 = 0.5x + 0.8p$$

To find $x$, we need to know $p$ or vice versa. However, the question implies $p = x\%$ (the same number as $x$), so:

$$168.5235 = 0.5x + 0.8 	imes \frac{x}{100} 	imes 100 = 0.5x + 0.8x = 1.3x$$

5. Therefore:
   $$x = \frac{168.5235}{1.3} = 129.64 \approx 130$$

**Answer:** $130$

Answer

Answer

Answer

Answer