If 30 ml solution of 20% alcohol is mixed with 20 ml solution of 25% alcohol, then what is the strength of alcohol in the mixture?

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Accepted Answer

To find the strength of alcohol in the mixture:

1. **Calculate the quantity of alcohol in each solution**:  
   - For the first solution (30 ml, 20% alcohol):  
     $$
     	ext{Quantity of alcohol} = \frac{20}{100} 	imes 30 = 6 \, 	ext{ml}.
     $$  
   - For the second solution (20 ml, 25% alcohol):  
     $$
     	ext{Quantity of alcohol} = \frac{25}{100} 	imes 20 = 5 \, 	ext{ml}.
     $$

2. **Find the total quantity of alcohol**:  
   Total alcohol = $$6 + 5 = 11 \, 	ext{ml}$$.

3. **Find the total volume of the mixture**:  
   Total volume = $$30 + 20 = 50 \, 	ext{ml}$$.

4. **Calculate the percentage strength of alcohol in the mixture**:  
   $$
   	ext{Percentage strength} = \frac{	ext{Total alcohol}}{	ext{Total volume}} 	imes 100 = \frac{11}{50} 	imes 100 = 22\%.
   $$

Thus, the strength of alcohol in the mixture is **22%**, and the correct answer is **(c)**.

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Answer

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