The average of five consecutive natural numbers is 13. If the next two natural numbers are also included, then find the new average.

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1. **Understand the given condition**:  
   The average of five consecutive natural numbers is 13.  
   Using the formula for average:  
   $$ 	ext{Total Sum} = 	ext{Average} 	imes 	ext{Number of Terms} $$  
   Total sum of five numbers = $$ 13 	imes 5 = 65 $$.

2. **Represent the five numbers**:  
   Let the five consecutive natural numbers be:  
   $$ n, (n+1), (n+2), (n+3), (n+4) $$.  
   The sum of these numbers is:  
   $$ n + (n+1) + (n+2) + (n+3) + (n+4) = 5n + 10 $$.  
   Equating to the total sum:  
   $$ 5n + 10 = 65 $$  
   Solve for $$ n $$:  
   $$ n = \frac{65 - 10}{5} = 11 $$.

3. **Include the next two numbers**:  
   The next two consecutive numbers are $$ n+5 $$ and $$ n+6 $$.  
   Add these to the sum of the first five numbers:  
   Total sum of seven numbers = $$ 65 + (11+5) + (11+6) = 65 + 16 + 17 = 98 $$.

4. **Find the new average**:  
   New average = $$ \frac{	ext{Total Sum}}{	ext{Number of Terms}} = \frac{98}{7} = 14 $$.

Thus, the new average is **14**, and the correct answer is **(c)**.

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