A can do a work in 12 days. B’s efficiency to do the work is 50% more than that of A. In how many days will B be able to do the work?

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Accepted Answer

1. **Understand the efficiency ratio**:  
   B's efficiency is 50% more than A's efficiency.  
   If A's efficiency is $$100$$, then B's efficiency is $$150$$.  
   The ratio of efficiencies between A and B is $$2:3$$.

2. **Calculate total work**:  
   Total work done by A in 12 days = $$	ext{Efficiency of A} 	imes 	ext{Number of Days}$$ = $$2s 	imes 12 = 24s$$.

3. **Determine time taken by B**:  
   Since B’s efficiency is $$3s$$, the time taken by B to complete the same work is:  
   $$
   	ext{Time} = \frac{	ext{Total Work}}{	ext{Efficiency of B}} = \frac{24s}{3s} = 8 \, 	ext{days}.
   $$

Thus, B alone will take **8 days** to complete the work, and the correct answer is **(a) 8**.

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