In a right triangle, the length of the hypotenuse is 17 cm. If the length of one side is 15 cm, then the area of the triangle is:

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1. **Use the Pythagorean theorem to find the other side**:  
   In a right triangle:  
   $$
   	ext{Hypotenuse}^2 = 	ext{Base}^2 + 	ext{Height}^2
   $$  
   Given: Hypotenuse = 17 cm, one side (Height) = 15 cm.  
   Solve for the other side (Base):  
   $$
   	ext{Base} = \sqrt{	ext{Hypotenuse}^2 - 	ext{Height}^2} = \sqrt{17^2 - 15^2} = \sqrt{289 - 225} = \sqrt{64} = 8 \, 	ext{cm}.
   $$

2. **Calculate the area**:  
   Area of a right triangle is given by:  
   $$
   	ext{Area} = \frac{1}{2} 	imes 	ext{Base} 	imes 	ext{Height}
   $$  
   Substituting values:  
   $$
   	ext{Area} = \frac{1}{2} 	imes 8 	imes 15 = 60 \, cm^2.
   $$

Thus, the area of the triangle is **60 $$cm^2$$**, and the correct answer is **(c)**.

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