What will be the area of a right-angled triangle whose hypotenuse is 10 cm and base is 6 cm?

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Accepted Answer

The given triangle is a right-angled triangle with a hypotenuse of 10 cm and base of 6 cm.

**Step 1:** Calculate the height using the Pythagoras theorem:  
Height ($$h$$) = $$ \sqrt{	ext{Hypotenuse}^2 - 	ext{Base}^2} $$  
$$
h = \sqrt{10^2 - 6^2} = \sqrt{100 - 36} = \sqrt{64} = 8 \, 	ext{cm}.
$$

**Step 2:** Calculate the area of the triangle:  
Area = $$ \frac{1}{2} 	imes 	ext{Base} 	imes 	ext{Height} $$  
$$
	ext{Area} = \frac{1}{2} 	imes 6 	imes 8 = 24 \, 	ext{sq cm}.
$$

Thus, the area of the triangle is **24 sq cm**.

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