A man invested Rs. 6500 at a compound interest rate of 10% per annum for 2 years in Scheme A. He then reinvested the amount received from Scheme A in the same scheme for another 2 years at the same rate. What is the approximate total interest earned by the man from the second investment?

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**Solution:**

1. First, calculate the amount after 2 years for the initial investment of Rs. 6500 at 10% compound interest.

The compound interest formula is:
   $$A = P 	imes \left(1 + \frac{r}{100}ight)^n$$

Where:
   - *P* = Principal = 6500
   - *r* = Rate of interest = 10%
   - *n* = Number of years = 2

Calculate the amount after 2 years:
   $$A = 6500 	imes \left(1 + \frac{10}{100}ight)^2 = 6500 	imes (1.1)^2 = 6500 	imes 1.21 = 7865$$

2. The man reinvests Rs. 7865 for another 2 years at the same rate and scheme.

Calculate the amount after the next 2 years:
   $$A_2 = 7865 	imes (1.1)^2 = 7865 	imes 1.21 = 9518.65$$

3. The interest earned in the second investment is:
   $$	ext{Interest} = A_2 - 	ext{Principal} = 9518.65 - 7865 = 1653.65 \approx 1692 	ext{ (closest option)}$$

**Answer:** Rs. 1692

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