Numbers from 3 to 51 are placed in a box. If a number is drawn from it, find the probability that the number drawn is a perfect cube.

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Accepted Answer

The numbers from 3 to 51 are considered. The total number of outcomes is:  
$$
51 - 3 + 1 = 49.
$$

Perfect cubes between 3 and 51 are $$2^3 = 8$$ and $$3^3 = 27$$. Thus, there are **2 perfect cubes**.

The probability of drawing a perfect cube is:  
$$
	ext{Probability} = \frac{	ext{Favorable Outcomes}}{	ext{Total Outcomes}} = \frac{2}{49}.
$$

Thus, the correct answer is **(d) $$ \frac{2}{49} $$**.

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Answer

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