If $(7.92)^3 + (7.92)^2 = -99.96 + (x)^2$, find the value of $x$.

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**Solution:**

1. First, calculate $(7.92)^2$:
   $$7.92 	imes 7.92 = 62.7264$$

2. Next, calculate $(7.92)^3$:
   $$7.92 	imes 62.7264 = 496.974048$$

3. Sum the two values:
   $$496.974048 + 62.7264 = 559.700448$$

4. According to the equation:
   $$(7.92)^3 + (7.92)^2 = -99.96 + x^2$$
   Substitute the sum:
   $$559.700448 = -99.96 + x^2$$

5. Rearranging to find $x^2$:
   $$x^2 = 559.700448 + 99.96 = 659.660448$$

6. Now, find $x$ by taking the square root:
   $$x = \sqrt{659.660448} \approx 25.68$$

7. Among the options, the closest perfect square is $25^2 = 625$, which is the nearest integer value for $x$.

**Answer:** $25$

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