Point A is 3m east of point B. Point D 4m north of point of C. Point K 7m west of point J. Point D 4m south of point of A. Point L 4m south of point G who 6m west of point F. Point E 5m east of point C and point B 5m north of point F. Point M 5m south of point E who 4m west of point N. Point K 3m north of Q. Point I is 4m east of point A. Point J is in 6m north of I.

Point W is 3 m east of point J and point V is 4 m north of point W. Given the positions of points as described, what is the shortest distance between point V and point L?

Question

Point A is 3m east of point B. Point D 4m north of point of C. Point K 7m west of point J. Point D 4m south of point of A. Point L 4m south of point G who 6m west of point F. Point E 5m east of point C and point B 5m north of point F. Point M 5m south of point E who 4m west of point N. Point K 3m north of Q. Point I is 4m east of point A. Point J is in 6m north of I.

Point W is 3 m east of point J and point V is 4 m north of point W. Given the positions of points as described, what is the shortest distance between point V and point L?

Accepted Answer

**Solution:**

1. From the given data, we first determine the coordinates of points V and L relative to a common origin.

2. Point W is 3 m east of point J, so if J is at $(x, y)$, then W is at $(x+3, y)$.

3. Point V is 4 m north of W, so V is at $(x+3, y+4)$.

4. From the problem's original data and relative positions, point L's coordinates can be deduced as $(x_L, y_L)$.

5. Using the distance formula between two points $(x_1, y_1)$ and $(x_2, y_2)$:
   $$	ext{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$

6. Substituting the values for points V and L, the distance calculates to:
   $$\sqrt{19^2 + 16^2} = \sqrt{361 + 256} = \sqrt{617}$$

**Answer:** $\sqrt{617} 	ext{ m}$

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