There was a loss of 22\% after selling an article at 40\% discount on the marked price. The shopkeeper then increased the marked price by 40\% but allowed the same discount percentage. After this change, he earned a profit of Rs. 184. Find the cost price of the article.

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**Solution:**

1. Let the cost price be $ x $ and the original marked price be $ y $.

2. Given: Selling at 40\% discount leads to a loss of 22\%.
   - Selling price (SP) = 60\% of $ y $ (since 40\% discount means selling at 60\% of marked price)
   - Loss of 22\% means:
     $$\text{SP} = 78\% \text{ of } x = 0.78x$$

3. Equate the two expressions for SP:
   $$0.78x = 0.60y$$
   $$\Rightarrow 78x = 60y$$
   $$\Rightarrow \frac{x}{y} = \frac{60}{78} = \frac{10}{13}$$
   So, $ x = \frac{10}{13} y $.

4. Now, the shopkeeper increases the marked price by 40\%:
   - New marked price = $ 140\% \text{ of } y = 1.4y $.

5. The discount remains the same at 40\%, so new selling price:
   $$\text{New SP} = 60\% \text{ of } 1.4y = 0.6 \times 1.4y = 0.84y$$

6. Given that after this change, the shopkeeper earns a profit of Rs. 184:
   $$\text{Profit} = \text{New SP} - \text{Cost Price} = 184$$
   $$0.84y - x = 184$$

7. Substitute $ x = \frac{10}{13} y $ into the above:
   $$0.84y - \frac{10}{13} y = 184$$

8. Calculate the left side:
   $$0.84y = \frac{84}{100} y = \frac{21}{25} y$$

So,
   $$\frac{21}{25} y - \frac{10}{13} y = 184$$

9. Find common denominator and simplify:
   $$\frac{21 \times 13}{25 \times 13} y - \frac{10 \times 25}{13 \times 25} y = 184$$
   $$\frac{273}{325} y - \frac{250}{325} y = 184$$
   $$\frac{23}{325} y = 184$$

10. Solve for $ y $:
    $$y = \frac{184 \times 325}{23} = 184 \times \frac{325}{23}$$

Since $ 23 \times 14 = 322 $, approximately:
    $$y = 184 \times 14.13 = 2600$$

11. Now find $ x $:
    $$x = \frac{10}{13} y = \frac{10}{13} \times 2600 = 2000$$

**Answer:** Rs. 2000

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