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From the top of an upright pole 17.75 m 17.75 \text{ m} 17.75 m high, the angle of elevation of the top of an upright tower was 60 ∘ 60^\circ 6 0 ∘ . ...

SSC SSC CGL Tier 2 Medium Triangle and its various kinds of centres MCQ

Question

From the top of an upright pole 17.75 m17.75 \text{ m} high, the angle of elevation of the top of an upright tower was 60∘60^\circ. If the tower was 57.75 m57.75 \text{ m} tall, how far away (in meters) from the foot of the pole was the foot of the tower?

Options

A.

4033\frac{40\sqrt{3}}{3}

B.

15136\frac{151\sqrt{3}}{6}

C.

7743\frac{77}{4}\sqrt{3}

D.

4033\frac{40\sqrt{3}}{3}

trigonometryangle of elevationright triangledistance calculation

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