Given that x x x women can complete a work in 2 y 2y 2 y days, 1.5 x 1.5x 1.5 x men can complete the same work in y y y days, and 2 x 2x 2 x children ...

Question

Given that xx women can complete a work in 2y2y days, 1.5x1.5x men can complete the same work in yy days, and 2x2x children can complete the same work in 3y3y days. Also, 8 women, 8 men, and 8 children together can complete the work in 221222 \frac{1}{2} days, and 9 men can complete the work in (y+20)(y + 20) days.

If (x6)(x - 6) women worked for (y6)(y - 6) days and (x6)(x - 6) men worked for (y10)(y - 10) days, then in how many days will the remaining work be completed by (x6)(x - 6) children?

Choose the correct option.

Options

A.

15223152 \frac{2}{3} days

B.

14813148 \frac{1}{3} days

C.

$145$ days

D.

$154$ days

E.

$158$ days

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