If sin ⁡ A = 4 5 \sin A = \frac{4}{5} sin A = 5 4 ​ , then ( 3 − tan ⁡ A ) ( 2 + cos ⁡ A ) (3 - \tan A)(2 + \cos A) ( 3 − tan A ) ( 2 + cos A ) is:

Question

If

sinA=45\sin A = \frac{4}{5}
, then
(3tanA)(2+cosA)(3 - \tan A)(2 + \cos A)
is:

Options

A.
125\frac{12}{5}
B.
133\frac{13}{3}
C.
135\frac{13}{5}
D.

5

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