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In triangle A B C ABC A BC , altitudes A D AD A D and B E BE BE are drawn to the corresponding bases. If ∠ B A C = 45 ∘ \angle BAC = 45^\circ ∠ B A C ...

CAT Medium Triangles MCQ

Question

In triangle

ABCABC
, altitudes
ADAD
and
BEBE
are drawn to the corresponding bases. If
∠BAC=45∘\angle BAC = 45^\circ
and
∠ABC=θ\angle ABC = \theta
, then

ADBE\frac{AD}{BE}
equals:

Options

A.
2sin⁡θ\sqrt{2} \sin \theta
B.
2cos⁡θ\sqrt{2} \cos \theta
C.
sin⁡θ+cos⁡θ2\frac{\sin \theta + \cos \theta}{\sqrt{2}}
D.
11
trianglesaltitudestrigonometry ratioscat 2022

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