Let △ A B C \triangle ABC △ A BC be an isosceles triangle such that A B AB A B and A C AC A C are of equal length. A D AD A D is the altitude from A A...

Question

Let

ABC\triangle ABC
be an isosceles triangle such that
ABAB
and
ACAC
are of equal length.
ADAD
is the altitude from
AA
on
BCBC
, and
BEBE
is the altitude from
BB
on
ACAC
. If
ADAD
and
BEBE
intersect at
OO
such that
AOB=105\angle AOB = 105^\circ
, then
ADBE\frac{AD}{BE}
equals:

Options

A.
2sin152 \sin 15^\circ
B.
cos15\cos 15^\circ
C.
2cos152 \cos 15^\circ
D.
sin15\sin 15^\circ
isosceles trianglealtitudestrigonometrycat 2023

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