The roots α \alpha α , β \beta β of the equation 3 x 2 + λ x − 1 = 0 3x^2 + \lambda x - 1 = 0 3 x 2 + λ x − 1 = 0 , satisfy 1 α 2 + 1 β 2 = 15. \frac{...

Question

The roots

α\alpha
,
β\beta
of the equation
3x2+λx1=03x^2 + \lambda x - 1 = 0
, satisfy
1α2+1β2=15.\frac{1}{\alpha^2} + \frac{1}{\beta^2} = 15.

The value of

(α3+β3)2(\alpha^3 + \beta^3)^2
is

Options

A.

9

B.

16

C.

4

D.

1

cat 2024rootsalgebraic equation

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